<pre id="bbfd9"><del id="bbfd9"><dfn id="bbfd9"></dfn></del></pre>

          <ruby id="bbfd9"></ruby><p id="bbfd9"><mark id="bbfd9"></mark></p>

          <p id="bbfd9"></p>

          <p id="bbfd9"><cite id="bbfd9"></cite></p>

            <th id="bbfd9"><form id="bbfd9"><dl id="bbfd9"></dl></form></th>

            <p id="bbfd9"><cite id="bbfd9"></cite></p><p id="bbfd9"></p>
            <p id="bbfd9"><cite id="bbfd9"><progress id="bbfd9"></progress></cite></p>

            12月4日數學機經解析

            發布時間:2017-11-30 編輯:少冰

              GRE數學滿分是幾乎所有中國考生的既定目標,而想要確保自己不會在考試中因為一時粗心而丟失分數,提前了解可能出現的考點陷阱就是必須做好的準備工作了。下面是小編為大家整理收集的關于12月4日數學機經的相關內容,歡迎大家的閱讀。

              題目

              1. If k is an integer and 121 < k^2 < 225,then k can have at most how many values?

              A. 3

              B. 4

              C. 5

              D. 6

              E. 7

              答案:D.

              解析:k可以是12,13,14,-12,-13,-14.

              2. Runner A ran 4/5 kilometer and Runner B ran 800 meters.

              Quantity A: The distance that A ran

              Quantity B: The distance that B ran

              A. Quantity A is greater.

              B. Quantity B is greater.

              C. The two quantities are equal.

              D. The relationship cannot be determined from the information given.

              答案:C

              解析:Quantity A=(4/5)*1000=800=Quantity B。

              3. x < y < z,

              Quantity A: (x + y + z)/3

              Quantity B: y

              A. Quantity A is greater.

              B. Quantity B is greater.

              C. The two quantities are equal.

              D. The relationship cannot be determined from the information given.

              答案:D

              解析:已知條件太少,AB大小都可以根據不同數據列出可能答案,因此無法判斷準確唯一解,選D。

              4. A reading list for a humanities course consists of 10 books, of which 4 are biographies and the rest are novels. Each student is required to read a selection of 4 books from the list, including 2 or more biographies. How many selections of 4 books satisfy the requirements?

              A. 90

              B. 115

              C. 130

              D. 144

              E. 195

              答案:D

              解析:10本書中,4本biographies,6本novel。現在biographies要選2本以上。

              思路1:正面解法

              所以可能情形有bio選2本(配nov選2)+bio選3本(配nov選1本)+bio選4本(配nov選0本)。

              即(C4取2乘C6取2)+(C4取3乘C6取1)+(C4取4乘C6取0)=115

              思路2:反向解法

              用全部扣除bio選0本(配nov選4)再扣bio選1本(配nov選3)

              利用C10取4-C4取0*C6取4-C4取1*C6取3 = 210 - 15 - 80 = 115

              5. In a graduating class of 236 students, 142 took algebra and 121 took chemistry. What is the greatest possible number of students that could have taken both algebra and chemistry?

              答案:121

              解析:可能不少人會用142+121-236=27的思路來解題,但問題是least possible number,同時也沒有表明只能選兩門課,因此有可能還有其他課可選,因此正確答案是眼前兩個交集的最大數,也就是142和121取最小數,121個學chemistry的都選了algebra。所以為121。

            最新推薦
            熱門推薦

                    <pre id="bbfd9"><del id="bbfd9"><dfn id="bbfd9"></dfn></del></pre>

                    <ruby id="bbfd9"></ruby><p id="bbfd9"><mark id="bbfd9"></mark></p>

                    <p id="bbfd9"></p>

                    <p id="bbfd9"><cite id="bbfd9"></cite></p>

                      <th id="bbfd9"><form id="bbfd9"><dl id="bbfd9"></dl></form></th>

                      <p id="bbfd9"><cite id="bbfd9"></cite></p><p id="bbfd9"></p>
                      <p id="bbfd9"><cite id="bbfd9"><progress id="bbfd9"></progress></cite></p>
                      飘沙影院